-0.096x^2+9.42x+6,96=0

Solution for -0.096x^2+9.42x+6,96=0 equation:

-0.096x^2+9.42x+6.96=0

a = -0.096; b = 9.42; c = +6.96;
Δ = b2-4ac
Δ = 9.422-4·(-0.096)·6.96
Δ = 91.40904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.42)-\sqrt{91.40904}}{2*-0.096}=\frac{-9.42-\sqrt{91.40904}}{-0.192}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.42)+\sqrt{91.40904}}{2*-0.096}=\frac{-9.42+\sqrt{91.40904}}{-0.192}
$